[olug] Subnet mask

[Bob McCoy]

Actually it would have to be 64 .. 95.  93 is not on a subnet boundary.
You would have 32 addresses in this subnet range (OK, actually 30 usable
addresses plus the reserved network address and the broadcast address),
therefore, 5 bits of host addressing ( 32 = 2 ** 5).  32 - 5 = 27 bits
of network addressing.  128 + 64 + 32 = 224.  Alternatively you could
have subtracted 32 from 256.  Therefore the subnet mask is
255.255.255.224, or it could be expressed 205.202.101.64/27 (three
additional bits into the Class C space).

Bob 

-----Original Message-----
From: olug-bounces at olug.org [mailto:olug-bounces at olug.org] On Behalf Of
Craig Wolf
Sent: Saturday, December 13, 2003 3:10 PM
To: olug at olug.org
Subject: [olug] Subnet mask

I am having a brain freeze and I cannot for the life of me figure this
out.  I have been given a range of numbers to use at my job and I cannot
figure out the subnet mask...Help!
The numbers are 205.202.101.64-205.202.101.93.  Class C address from
authority.  I know that by thinking about it, it is divided into 4
subnets, right? (30 numbers into 128 is 4 times+).  ugh.  My head hurts
today...

Craig Wolf
Linux Web Server Support
Desktop/Network Specialist
402-894-6283

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